Re: [Haskell-cafe] iterative algorithms: how to do it in Haskell?

G'day all. Quoting Chris Kuklewicz <haskell@list.mightyreason.com>:

The compiler may not deforest that list, so creating the list may be a small overhead of this method.

And in return, you get: - Code that is smaller than the imperative version, AND - a reusable function, making the next incarnation of an algorithm like this even shorter. For most interesting cases, the cost of f and goOn will surely dominate anyway.

Note that "f x" should be "f a" above.

Yes, you're right. I abstracted out "f" after testing and before posting. Cheers, Andrew Bromage