
29 Sep
2009
29 Sep
'09
2:16 a.m.
Magicloud,
There are numerous ways to construct such a function. Hoogling
"(Fractional a, Integral b) => a -> b" brings up a host of functions
that would be of use here in combination with fromIntegral.
Thomas
On Mon, Sep 28, 2009 at 11:11 PM, Magicloud Magiclouds
Hi, Here is an example: let l = fun num in if isIntegral l then l else 0 How to do the isIntegral thing?
On Tue, Sep 29, 2009 at 1:58 PM, Magicloud Magiclouds
wrote: Hi, In other weak-type language, `round i == i` would work. But in haskell, what should I do? Thanks. -- 竹密岂妨流水过 山高哪阻野云飞
-- 竹密岂妨流水过 山高哪阻野云飞
_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe