20 Sep
2010
20 Sep
'10
3:52 p.m.
Alex Rozenshteyn schrieb:
I feel that there is something that I don't understand completely: I have been told that Haskell does not memoize function call, e.g.
slowFib 50 will run just as slowly each time it is called. However, I have read that Haskell has call-by-need semantics, which were described as "lazy evaluation with memoization"