Hi, Andre,
map (foo 5) my_list_of_lists_of_doubles
...But how to do that (if possible) when I invert the parameters list ?!
Let me add one more solution, and then summarize: The problem disapears if you use a list comprehension instead of map: [foo x 5 | x <- my_list_of_lists_of_doubles] List comprehensions are funny. Sometimes, they are powerful, consise, and crystal clear. Other times they can seem wordy and confusing. In this case it works well. OK, so the four solutions that have been suggested are: 1. map (flip foo 5) my_list_of_lists_of_doubles 2. map (`foo` 5) my_list_of_lists_of_doubles 3. map (\x->foo x 5) my_list_of_lists_of_doubles 4. [foo x 5 | x <- my_list_of_lists_of_doubles] (1) and (2) are closest to what you originally wanted to write. They do not neatly generalize beyond the second parameter. (3) is more general - but a little less clear. (4) is the most different from your original idea. In a certain sense, it is even more general than (3). In this case, it is also simple and clear - though you may not always be so lucky. BTW - great question! Regards, Yitz