Hi Debasish, You can also write (f1 >=> f2 >=> f3) acc or f1 acc >>= f2 >>= f3 or foldr (>=>) [f1, f2, f3] pure acc Regards, Li-yao On 2/1/20 1:54 PM, Debasish Ghosh wrote:
Hi -
How can I generalize the following pattern to an arbitrary list of functions ?
compose :: (Monad m) => (Foo -> m Foo) -> (Foo -> m Foo) -> (Foo -> m Foo) -> Foo -> m Foo compose f1 f2 f3 acc = do a <- f1 acc b <- f2 a f3 b
Any help please .. regards.
-- Debasish Ghosh http://manning.com/ghosh2 http://manning.com/ghosh
Twttr: @debasishg Blog: http://debasishg.blogspot.com Code: http://github.com/debasishg
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