Fibonacci numbers implementations in Haskell one of the classical examples. An example I found is the following: fibs :: [Int] fibs = 0 : 1 : [ a + b | (a, b) <- zip fibs (tail fibs)] To get the k-th number you do the following: Result = fibs !! k It is elegant but creates a list of all Fibonacci numbers less than k-th, and the code is not very readable :). I wrote my own Fibonacci numbers generator: fib :: Int -> [Int] fib 0 = [0,0] fib 1 = [1,0] fib n = [sum prevFib, head prevFib] where a = fib (n - 1) To get the k-th number you do the following: result = head (fib k) It does not generate full list of Fibonacci numbers, but keeps only 2 previous numbers, and has only one recursive call. Because the list always has only 2 elements using the functions head and sum is a bit overkill. Can we do better? _________________________________________________________________ Are you using the latest version of MSN Messenger? Download MSN Messenger 7.5 today! http://join.msn.com/messenger/overview