Re: [Haskell-cafe] forall and a parse error

3 Jul 2006


      On 7/3/06, David House  wrote:
...
On 03/07/06, Neil Mitchell  wrote:
...
In normal Haskell, I tend to view [x] as equivalent to [(x)] (provided
that x is not a tuple) but in this case it has a different meaning -
albeit both are erronous meanings.
How would tuples make a difference?
[1,2] /= [(1,2)] - the brackets have changed the semantics, because of
the tupling. Haskell has two distinct types of brackets, (x) for
grouping, (x,y) for tupling. For that reason, there is no way to write
the 1 item tuple - despite the fact that some compilers (Yhc/nhc)
define and use it internally.

Thanks

Neil