29 Dec
2011
29 Dec
'11
12:29 p.m.
On Thu, Dec 29, 2011 at 11:14 AM, Gregg Reynolds
On Dec 29, 2011, at 11:01 AM, Iustin Pop wrote:
And to clarify better my original email: yes, (bar x) always gives you back the same IO action;
More precisely: the same *type*.
I'm confused - what do you mean by "type"? I don't think that Iustin's statement needs any sort of qualifier - (bar x) always returns the same IO action when called with the same value for x, no matter how many times you call it. Antoine