Re: [Haskell-cafe] Generating random arguments for a function

Yes - I was just checking the first QuickCheck paper to see how the authors did this. You would need a new type class that works like `Testable` and the versions of associated machinery `forAll` and `evaluate` to unroll function application. On 13 January 2013 09:28, Roman Cheplyaka wrote:

This can be done with relatively simple type class hackery. In fact, QuickCheck already does that in order to generate arguments and print them in case of failure.

Roman