
19 Mar
2009
19 Mar
'09
12:25 p.m.
I always feel that the compiler should do such optimizations for me :) On 19 Mar 2009, at 16:21, Neil Mitchell wrote:
I've used a similar function myself, but why write it in such a complicated way? How about
lfp :: Eq a => (a -> a) -> a -> a lfp f x | f x == x = x | otherwise = lfp f (f x)
I've used a similar function too, but your version computes f x twice per iteration, I wrote mine as:
fix :: Eq a => (a -> a) -> a -> a fix f x = if x == x2 then x else fix f x2 where x2 = f x
I find this fix much more useful than the standard fix.
Thanks
Neil