Re: [Haskell-cafe] Haskell guards

On Thu, Sep 20, 2007 at 05:20:46PM +0400, Victor Nazarov wrote:

I still can't remember how guards are treated in Haskell. Here is the code snippet in question:

foo a | a == 1 = 6 foo a | a == 2 = 7 foo a = 8

Would Haskell fall through to the third alternative if a is not equal to 1 or 2. I know that this can be rewritten more sanely, but I just consider guard behavior. What would be the value of (foo 3)?

8. It falls through if no guards in a rhs match. Stefan