[Haskell-cafe] Re: problems with square roots...

------------ From: Daniel Carrera Hey, The sqrt function is not doing what I want. This is what I want: round sqrt(2) --------------------------------------------------- Daniel, A lot of Haskell folks like to avoid parentheses as much as possible, and there's a really convenient way to do this. There is a Prelude function ($) f x = f x which is right-associative, so you can write round $ sqrt x == round (sqrt x) This becomes really convenient when multiple application is involved: print $ round $ sqrt x == print (round (sqrt x)) -Chad