Re: [Haskell-cafe] Prolog-style patterns

You can achieve something similar with the ViewPatterns language extension.

member _ [] = False member x (((x ==) -> True) : _) = True member x (_ : xs) = member x xs Hi Tillmann,

there are a couple of ways to achieve this in Haskell, for example using guards: member :: Eq a => a -> [a] -> Bool member _ [] = False member y (x:_) | x == y = True member y (_:xs) = member y xs The goal of my proposal is to provide a concise syntax, whereas ViewPatterns are very verbose and guards are slightly verbose. I want something simple and something that is very intuitive if you've programmed in Prolog :) Janek