
15 Aug
2012
15 Aug
'12
2:55 p.m.
On 12-08-15 03:20 AM, wren ng thornton wrote:
(forall a. P(a)) -> Q <=> exists a. (P(a) -> Q)
For example: A. (forall p. p drinks) -> (everyone drinks) B. exists p. ((p drinks) -> (everyone drinks)) In a recent poll, 100% of respondents think A true, 90% of them think B paradoxical, and 40% of them have not heard of the Smullyan drinking paradox. Hehe! http://www.vex.net/~trebla/weblog/any-all-some.html