26 Jul
2007
26 Jul
'07
12:03 p.m.
Hi Jon, On Thu, 26 Jul 2007, Jon Harrop wrote:
If you have a boolean-or expression:
a || b
will "a" be evaluated before "b" in Haskell as it is in other languages?
Yes, I believe it is defined thus: True || _ = True _ || True = True _ || _ = False Therefore it is strict in its first argument (it needs to evaluate its first argument in order to know which pattern match to take). Chris.