My question was meant in the context of the makeVerifier function, which is passed a lambda expression. It's my understanding that Haskell lambda expressions can have only a single parameter, which is why I changed the function parameter to a pair, (i,d).
How would it be done otherwise?
Michael
--- On Sun, 4/12/09, Daniel Fischer
Example please.
Michael
Curried: f :: a -> b -> c amenable to partial application. Uncurried: g :: (a,b) -> c not easy to apply partially. The Prelude contains curry :: ((a,b) -> c) -> (a -> b -> c) uncurry :: (a -> b -> c) -> ((a,b) -> c) to convert if needed.