29 Mar
2010
29 Mar
'10
9:16 a.m.
a -> b -> c is a -> (b -> c)
domain : a
codomain : b -> c (which is a valid Haskell type, of the functions from b to
c)
2010/3/29 Günther Schmidt
Hi,
I can easily see how one identifies the domain and co-domain of a unary function.
How would the domain of a function be expressed that takes more than one argument and arguments of different type?
Günther
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