nowgate:
Hi Donald,
I think you misunderstood what I was asking. There's not two cases. Maybe I'm not saying it sufficiently well but the function ALWAYS just returns a function that always returns the original argument to ALWAYS no matter what else you give the resulting function.
when one is define as follows
one = always 1
then
one 4 1 one "abc" 1 one (2,3) 1 one [0,4,8,2] 1 map one ["one","two","three"] [1,1,1]
The mapping example is just an alternative way of illustrating the functionality. No matter what the defined function is given it always gives back the original value give to ALWAYS.
Ah yes, I must have missed the 'map one' in the original post. Hence I thought you were looking for different behaviour for lists. My mistake. Prelude.const is your friend :-) -- Don