[Haskell-cafe] why cannot i get the value of a IORef variable ?

let aaa = unsafePerformIO $ newIORef [] writeIORef aaa [1,2,3] readIORef aaa [(),(),()]

sincerely! -- View this message in context: http://www.nabble.com/why-cannot-i-get-the-value-of-a-IORef-variable---tp260... Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.