Hello all, It is either too difficult to get two integers of a bytestring, in which case something should be done to ease the process or I should learn much more Haskell. I guess the latter is the correct guess. I have a bytestring containing two naturals. I was to get them as efficiently as possible. Here's my code: parseHeader :: BS.ByteString -> (Int, Int) parseHeader bs = let first = BS.readInt $ BS.dropWhile (not . isDigit) bs in if(isNothing first) then error "Couldn't find first natural." else let second = BS.readInt $ BS.dropWhile (not . isDigit) $ snd $ fromJust first in if(isNothing second) then error "Couldn't find second natural." else (fst $ fromJust first, fst $ fromJust second) This seems to work:
parseHeader $ BS.pack "hello 252 359" (252,359)
Is there a better way? Cheers, -- Paulo Jorge Matos - pocm at soton.ac.uk http://www.personal.soton.ac.uk/pocm PhD Student @ ECS University of Southampton, UK