This is a Hard Problem in Haskell.
Let me ask you, how many parameters does this function take?
a = (\x -> x)
How many parameters does this function take?
b = (\f x -> f x)
How many parameters does this function take?
c = (\f x y -> f x y)
What if I call
a (+)?
-- ryan
On Tue, May 5, 2009 at 9:49 AM, Nico Rolle
Hi everyone.
I have a problem. A function is recieving a lambda expression like this: (\ x y -> x > y) or like this (\ x y z a -> (x > y) && (z < a)
my problem is now i know i have a list filled with the parameters for the lambda expression. but how can i call that expression? [parameters] is my list of parameters for the lambda expression. lambda_ex is my lambda expression
is there a function wich can do smth like that?
lambda _ex (unfold_parameters parameters)
best regards _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe