Re: [Haskell-cafe] How to get a file path to the program invoked?

On Thu, Dec 1, 2011 at 3:41 PM, Simon Hengel wrote:

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How to get this path in Haskell?

If I understand you correctly, you want

  takeDirectory `fmap` getProgName

I think getProgName does not give you the full path, but only the program name.

Neither does $0, does it? It depends on how the program is called. You can always use System.Directory.getCurrentDirectory with System.FilePath.{isRelative,replaceDirectory} if you somehow need the full path. Note, however, that not even this is generally guaranteed to be correct. Cheers, -- Felipe.