Re: [Haskell-cafe] New Eq instance

rodrigo.bonifacio wrote:

instance Eq Step where Step id1 scenario1 action1 state1 response1 == Step id2 scenario2 action2 state2 response2 = id == id _ == _ = False

Almost. You just used 'id' and 'id' when you meant 'id1' and 'id2'.

instance Eq Step where Step id1 scenario1 action1 state1 response1 == Step id2 scenario2 action2 state2 response2 = id1 == id2

but it's a common idiom not to bother to name unused parameters, so:

instance Eq Step where Step id1 _ _ _ _ == Step id2 _ _ _ _ = id1 == id2

(and the default case is never reached so you don't need it)

ps.: sorry, this kind of basic question can be sent to this list?

Yes, that's fine. You may get quicker answers if you hop onto IRC at #haskell, though. Jules