14 Jul
2005
14 Jul
'05
2:13 p.m.
On 2005-07-07, Henning Thielemann
My point was that vectors naturally do _not_ represent linear maps at all, but they are the objects linear maps act on. If I process an audio signal or an image I can consider it well as vector but why should I consider it as linear map?
Yes, they do. given a vector "a" in R^n, there are natural, invertible maps co(x): R^n -> R = (a dot x), and scale(b) : R -> R^n = (b * a). These contain all the information in the vector, and do come up naturally in some cases. (Consider a similarity metric on images -- co is a natural one). -- Aaron Denney -><-