8 Apr
2010
8 Apr
'10
3:13 a.m.
Jason: Thanks for the reply.
I suspect the solution is to correctly tell Haskell what type you expect and then hopefully HDBC will do the conversion. For example, using fromSql: http://software.complete.org/static/hdbc/doc/Database-HDBC.html#v% 3AfromSql
Yes. I can use fromSql to convert the result back to an appropriate numerical type. But internally the numeric data has still been converted to an intermediate string representation. I'm wondering if this is intentional, and whether it matters. Tim