Use the type lits Nat solver plugin by Christian B, or a userland peano
encoding. Sadly ghc does have any builtin equational theory so you either
need to construct proofs yourself or use a plugin.
I'm personally doing the plugin approach. If you would like to construct
the proofs by hand I'll dig up some examples later today if you like.
On Saturday, April 30, 2016, Baojun Wang
Hi List,
When I try to build below program, the compiler complains
Couldn't match type ‘n’ with ‘1 + (n - 1)’ …
Why GHC (7.10.3) cannot do type level natural number arithmetic? `` n /= 1 + (n-1)`` at type level?
-- | main.hs {-# LANGUAGE ScopedTypeVariables #-} {-# LANGUAGE FlexibleInstances #-} {-# LANGUAGE GADTs #-} {-# LANGUAGE PolyKinds #-} {-# LANGUAGE KindSignatures #-} {-# LANGUAGE TypeOperators #-} {-# LANGUAGE DataKinds #-} {-# LANGUAGE OverloadedStrings #-} {-# LANGUAGE DeriveGeneric #-}
module Main where
import qualified Data.ByteString as B import Data.ByteString(ByteString) import Data.Serialize -- require cereal
import GHC.TypeLits
data Scalar :: Nat -> * -> * where Nil :: Scalar 0 a Cons :: a -> Scalar m a -> Scalar (1+m) a
instance (Serialize a) => Serialize (Scalar 0 a) where get = return Nil put _ = return $ mempty
instance (Serialize a) => Serialize (Scalar n a) where get = do x <- get :: Get a xs <- get :: Get (Scalar (n-1) a) return $! Cons x xs put (Cons x xs) = do put (x :: a) put xs
--
/tmp/vect1/app/Main.hs:31:15: Couldn't match type ‘n’ with ‘1 + (n - 1)’ … ‘n’ is a rigid type variable bound by the instance declaration at /tmp/vect1/app/Main.hs:27:10 Expected type: Scalar n a Actual type: Scalar (1 + (n - 1)) a Relevant bindings include xs :: Scalar (n - 1) a (bound at /tmp/vect1/app/Main.hs:30:5) get :: Get (Scalar n a) (bound at /tmp/vect1/app/Main.hs:28:3) In the second argument of ‘($!)’, namely ‘Cons x xs’ In a stmt of a 'do' block: return $! Cons x xs Compilation failed.
- baojun