
7 Nov
2007
7 Nov
'07
2:47 p.m.
When discussing the complexity of fib don't forget that integer
operations for bignums are no longer constant time.
-- Lennart
On Nov 7, 2007 6:55 AM, Henning Thielemann
On Tue, 6 Nov 2007 ajb@spamcop.net wrote:
However, this is still an O(log n) algorithm, because that's the complexity of raising-to-the-power-of. And it's slower than the simpler integer-only algorithms.
You mean computing the matrix power of
/1 1\ \0 1/
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