Hello, I'm new at haskell and I have the following question: let's say I type the following: function = foldr until Now my first question is what is the type of this function? Well let's see what the type of until and foldr is: until :: (a -> Bool) -> (a -> a) -> a -> a foldr :: (a -> b -> b) -> b -> [a] -> b So I would be thinking: we fill until in the position of (a -> b -> b) so, a correspond with (a -> Bool) and b correspond with (a -> a) and b correspond with a. Hmm a small problem, I think we can divide that as follows: b1 corresponds with (a -> a) and b2 corresponds with a. So I get: foldr until :: b1 -> [a] -> b2 foldr until :: (a -> a) -> [a -> Bool] -> a Is this a correct way of thinking or am I wrong? And another question is: can someone give me an example how this can be executed? All my code that I tried to execute resulted in errors with "foldr until". Thanks!