30 Nov
2004
30 Nov
'04
8:06 p.m.
On Tue, 2004-11-30 at 13:52 +0000, Jules Bean wrote:
In the same sense, you could try
(map f [1..]) == (map g [1..])
and it will return False quickly if they are different, but it will run forever if they are the same.
For some very generous definition of "quickly" :) Bernie.