Re: [Haskell-cafe] Equality of functions

On Tue, 2004-11-30 at 13:52 +0000, Jules Bean wrote:

In the same sense, you could try

(map f [1..]) == (map g [1..])

and it will return False quickly if they are different, but it will run forever if they are the same.

For some very generous definition of "quickly" :) Bernie.