20 Jan
2010
20 Jan
'10
7:40 a.m.
Doesn't haddock define __HADDOCK__ by itself?
That appears to be a common misconception. The discussion on this ticket [1] indicates that haddock does *not* define __HADDOCK__. So I can not rely on it being defined. Therefore I would like to define it myself, but only in the case that haddock is being run on my code. 1 - http://trac.haskell.org/haddock/ticket/76