Re: [Haskell-cafe] Splitting list with predicate

14 Mar 2010

      Thanks all,

Wouldn't one need to know the order of the arguments?

(a -> Bool) -> [a] -> ([a], [a])

Michael

--- On Sun, 3/14/10, Simon Hengel  wrote:

From: Simon Hengel 
Subject: Re: [Haskell-cafe] Splitting list with predicate
To: "michael rice" 
Cc: haskell-cafe@haskell.org
Date: Sunday, March 14, 2010, 3:45 PM
...
Most excellent! Thanks.
I frequently use Hoogle[1] when I need a function, that I think must
exist, but do not know how it is named. Try:
(a -> Bool) -> [a] -> ([a], [a])

With the recipe from [2] you may even invoke hoogle from within ghci:

ghci> :hoogle (a -> Bool) -> [a] -> ([a], [a])

Hope that helps.

Cheers,
Simon

[1] http://haskell.org/hoogle/
[2] http://www.haskell.org/haskellwiki/Ghci#Hoogle