On 17 Dec 2010, at 20:04, michael rice wrote:
I don't understand this error message. Haskell appears not to understand that 1 is a Num.
As it clearly states in the error message, it doesn't understand that [Int] is a Num - and it's not. "No instance for Num something" usually indicates that you're trying to use an integer literal - in this case, "1" - as this "something". The problem is that your "lst" has the type "IO [Int]" (which is the same as "IO ([] Int)"). "fmap" has the type "(a -> b) -> f a -> f b", so, it tries to unify the type of "(+1)" with "[Int] -> something" - which, probably, isn't what you've meant. In fact, I'm pretty sure you wanted "lst" to have the type "[Int]" (= "[] Int"), without "IO". You can do that using "<-" instead of "let": main = do lst <- fst [1,2,3,4,5] return (fmap (+1) lst)
Prelude> :t 1 1 :: (Num t) => t Prelude> :t [1,2,3,4,5] [1,2,3,4,5] :: (Num t) => [t] Prelude>
Michael
===================
f :: [Int] -> IO [Int] f lst = do return lst
main = do let lst = f [1,2,3,4,5] fmap (+1) lst
===============================
Prelude> :l test [1 of 1] Compiling Main ( test.hs, interpreted )
test.hs:5:17: No instance for (Num [Int]) arising from the literal `1' at test.hs:5:17 Possible fix: add an instance declaration for (Num [Int]) In the second argument of `(+)', namely `1' In the first argument of `fmap', namely `(+ 1)' In the expression: fmap (+ 1) lst Failed, modules loaded: none. Prelude>
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