Re: [Haskell-cafe] foldr (.) id

Funny, I was thinking this morning about using something like this to convert to/from Church numerals: church n = foldl (.) id . replicate n unchurch f = f succ 0 I think it's a nice pattern. Nick On Friday, October 26, 2012 11:41:18 AM Greg Fitzgerald wrote:

Hi Haskellers,

I've recently found myself using the expression: "foldr (.) id" to compose a list (or Foldable) of functions. It's especially useful when I need to map a function over the list before composing. Does this function, or the more general "foldr fmap id", defined in a library anywhere? I googled and hoogled, but no luck so far.

Thanks, Greg