22 Dec
2009
22 Dec
'09
5:37 p.m.
On Tue, Dec 22, 2009 at 09:03:44AM -0800, slemi wrote:
this allows me to use the (^^) powering operator, which works fine with non-zero exponents. however to my surprise when i try (^^ 0) the answer is (Scalar 1), and not the identity matrix as expected. does this mean that (a ^^ 0) is not defined as (a ^^ 1 * a ^^ (-1)) (or better yet (a / a)) in the prelude? if so, can i redefine it so that it gives the right answer? i am also very interested in how ghci got the answer (Scalar 1), it seems quite magical:)
(^^ 0) == const 1, see this link: http://haskell.org/ghc/docs/latest/html/libraries/base-4.2.0.0/src/GHC-Real.... -- Felipe.