There's a lot to chew on (thank you!), but I'll just take something I can handle for now. Dan Doel wrote:
An existential:
exists a:T. P(a)
is a pair of some a with type T and a proof that a satisfies P (which has type P(a)). In Haskell, T is some kind, and P(a) is some type making use of a. That doesn't mean that there is only one a:T for which P is satisfied. But it *does* mean that for any particular proof of exists a:T. P(a), only one a:T is involved. So if you can open that proof, then you know that that is the particular a you're dealing with, which leads to the problems in the grandparent.
re: Constructivity and the opening of a proof A form of the theorem that the primes are infinite goes "Given a finite set of primes, there's a prime bigger than any of them." The usual proof is constructive since factorization is algorithmic, but I don't see why a priori, applications of this theorem on a given input should always yield the same prime when more than one factor exists. Is non-deterministic choice forbidden in constructive math? A cursory google seems to suggest that if not, it's at least a bête noire to some. -- View this message in context: http://www.nabble.com/forall---ST-monad-tp22024677p22100873.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.