Jon Strait wrote:
I'm reading the third (bind associativity) law for monads in this form:
m >>= (\x -> k x >>= h) = (m >>= k) >>= h
Arguably, that law would be better stated as:
(h <=< k) <=< m = h <=< (k <=< m)
This wouldn't be so unintuitive.
- Jake
