Re: [Haskell-cafe] problem with regex replace with back references

On Monday 24 May 2010 17:08:50, Juan Maiz wrote:

I'm trying use subRegex to replace using back references just like the docs says: http://hackage.haskell.org/packages/archive/regex-compat/0.92/doc/html/T ext-Regex.html#v%3AsubRegex

But when i try to replace with \1 i got \SOH and not "e". Can anyone help?

subRegex (mkRegex "e") "hello" "\1" => "h\SOHllo"

Try subRegex (mkRegex "e") "hello" "\\1"

Thanks in advance