Re: [Haskell-cafe] The C Equiv of != in Haskell

On 29/05/07, Daniel McAllansmith wrote:

Just in case there was some sort of miscommunication, the actual answer to your question is (/=) :: a -> a -> Bool, as Neil said.

Almost, (/=) :: Eq a => a -> a. (Just for completeness.) -- -David House, dmhouse@gmail.com