Re: [Haskell-cafe] 回复： Replace list item with list.

There is a function "concatMap" to simplify "concat $ map". Furthermore, you could use inline notation as follow: concatMap (\x -> x == "z" then B else [x]) A On Sat, Nov 4, 2017 at 7:50 AM, Денис Мирзоев wrote:

If you sure "z" is the last element of A you can use

init A ++ B

if it's somwhere in the middle consider

cocat $ map f A where f x | x == "z" = B | otherwise = [x]

On Sat, Nov 4, 2017 at 2:41 PM, Денис Мирзоев wrote:

...

If you sure "z" is the last element of A you can use

init A ++ B

if it's somwhere in the middle consider

cocat $ map f A where f x | x == "z" = B | otherwise = [x]

On Sat, Nov 4, 2017 at 1:57 PM, FlyingSheep wrote:

...

(take 2 A) ++ B

------------------ 李 鹏 四川大学计算机学院

------------------ 原始邮件 ------------------ *发件人:* "mirone"; *发送时间:* 2017年11月4日(星期六) 晚上6:48 *收件人:* "haskell-cafe"; *主题:* [Haskell-cafe] Replace list item with list.

Hello everyone! If I have a list A : ["x", "y", "z"] and a list B: ["f", "g"]. Here is my question: What's the simplest way to replace "z" in the list A by list B, and get ["x", "y", "f", "g"] ?

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