
See the http://hackage.haskell.org/package/split package. You should
be able to do this by splitting the string on comma, and then
splitting the result on 0, plus some plumbing.
Luke
On Mon, Feb 21, 2011 at 11:46 PM, z_axis
I want to split "2,15,33,0,8,1,16,18" to ([2,15,33],[8,1,16,18]). the "0" will by discarded.
However, it seems that there isnot any standard function to do it.
Sincerely!
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