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Jon Cast wrote:
Anyway, the second tutorial is correct: if all guards on pattern1 fail, pattern2 will be tried next. See Section 3.17.3 in the Haskell Report [1]. Btw., which was the first tutorial?
Anyway, the second tutorial is correct: if all guards on pattern1 fail, pattern2 will be tried next. See Section 3.17.3 in the Haskell Report [1].
Btw., which was the first tutorial?
Unfortunately, I cannot remember.
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