This looks like foldr, specifically:
f = foldr (.) v
so really, there's no way of telling what the operator could be, other
than that:
(.) :: a -> b -> b
where
f :: [a] -> b
v :: b
BTW, I find that most of your emails are in a very large font size. Do
other people notice this? It's not very nice to read. Gmail's 'Show
Original' feature tells me that the HTML version of your message
contains <font size=3> near the start.
On 19/09/2007, PR Stanley
Hi Here's another one: f [] = v f (x:xs) = x . f xs The "." is supposed to denote a generic operator - f [] maps to some value v and applied to non-empty list applies head to ? operator. Thanks, Paul
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