10 Nov
2006
10 Nov
'06
1:39 p.m.
On 11/10/06, Dougal Stanton
As you noted that doesn't seem right --- how does compile capture its input? Well, the (.) operator is slightly different. It captures variables and passes them into the 'innermost' function, a bit like this:
That is a great explanation. I've got a much better understanding of the operator now - thanks very much! Justin