Re: [Haskell-cafe] Should `(flip (^^))` work?

Mauricio wrote:

Hi,

I tested the expression below and it doesn't work. Is there some way to achieve that (i.e., turning an expression inside parenthesis into an operator)?

2 `(flip (^^))` (3%4)

Another solution if you don't like defining extra (-|) and (|-) operators is:

($2) (flip (^^)) (3%4)

The right section of function application is type lifting. The general form of this construction is:

($x) (f a b c...) y z...

Which is equal to (f a b c... x y z...). That is, the construction lets you raise any argument out to before the function, thus making the partially applied function into an infix between |x| and |y x...|. -- Live well, ~wren