8 Jan
2011
8 Jan
'11
5:24 p.m.
On Sat, Jan 8, 2011 at 5:07 PM, Tony Morris
Thanks guys for all the solutions. A slight correction below.
On 09/01/11 03:54, David Menendez wrote:
Naturally, if you also have pure and fmap, you also have a monad.
You have a pointed functor but not necessarily a monad.
You perhaps missed the word "also". If you have join, and you also
have pure and fmap, then you have a monad.
That's admittedly a little fuzzy about what it means to have join,
since the laws join must satisfy are defined in terms of fmap and
pure.
--
Dave Menendez