Re: [Haskell-cafe] Reinventing the wheel? Does any existing package provide an applicatively lifted (>>) ?

Am 28.09.2017 um 12:57 schrieb Jeffrey Brown:

...

or, equivalently:

        a `andthen` b = (>>) <$> a <*> b

for which http://pointree.io http://pointree.io/ dutifully gives me:

      andthen = (<*>) . ((>>) <$>)

That link is not working for me, and Google isn't finding it, and it sounds like a useful thing.

Theres just an `f` missing. Correct link is probably http://pointfree.io/