Use the isTrue# function which is made visible by importing GHC.Base.
isTrue# (x <=# y) :: Bool
You can show an Int# by wrapping it up in an I# data constructor and
applying show to it:
x# :: Int#
show (I# x#) ::String
You can make the I# data constructor visible via GHC.Base like above.
Hope that helps!
Rahul
On Wed, Nov 2, 2016 at 11:20 AM, Richard A. O'Keefe
I have x, y :: Int# I expect that x <=# y :: Bool but ghc 7.8 says Couldn't match expected type ‘Bool’ with actual type ‘Int#’ In the expression: x <=# y In an equation for ‘b’: b = x <=# y
I have MagicHash and I've imported the right modules so that <=# is recognised as *something*, but at this point I'm baffled.
I'm also not clear on how I can show an Int#.
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-- Rahul Muttineni