You can use Data.Conduit.Lazy for this.
https://www.stackage.org/haddock/lts-11.14/conduit-extra-1.3.0/Data-Conduit-...
On Thu, Jun 21, 2018, 12:13 PM Jon Fairbairn
Suppose I’m writing some code using Conduits, but need to use some old function f::[a]->[b] (defined in a library somewhere) that transforms a lazy list.
Is there a way of turning f into a Conduit without ending up with all of the list being in memory? ie something that looks like
toConduit:: ([a]->[b]) -> ConduitT a b m ()
I’ve got nowhere with Hoogle or Hayoo -- Jón Fairbairn Jon.Fairbairn@cl.cam.ac.uk
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