
Hi Folks, I had to transform Packed Decimal file into csv format (does anybody here know what this Mainframe format is?). Because of the file size I could not do this on mainframe directly. So I've created simply program using ByteString. Generally I'm happy with my solution: pgm processes arroud 2MB/s on my pc, so my 3GB file was transformed in reasonable 30 min time. My question is: how to do this faster? {code} module Main where import qualified Data.ByteString.Lazy as B main = B.getContents >>= myPrint . myConcat . B.unpack myConcat = myConcat' 0 myConcat' :: (Integral a) => Integer -> [a] -> [Integer] myConcat' _ [] = [] myConcat' acc (x:xs) = case x `mod` 16 of 12 -> (10*acc + (restOf . fromIntegral) x) : myConcat' 0 xs 13 -> ((-10)*acc + (restOf . fromIntegral) x) : myConcat' 0 xs 15 -> (10*acc + (restOf . fromIntegral) x) : myConcat' 0 xs 10 -> fail $ show acc 11 -> fail $ show acc 14 -> fail $ show acc v -> myConcat' (100*acc + (numberOf . fromIntegral) x) xs where restOf n = (n - 12) `div` 16 numberOf n = n - 6 * (n `div` 16) myPrint [] = return () myPrint xs = mapM_ myShow (take 14 xs) >> putStrLn "" >> myPrint (drop 14 xs) myShow x = (putStr . show) x >> putStr ";" {code} I knew that csv output had to be 14 fields per line. Best, Bartek