
26 Jul
2010
26 Jul
'10
10:12 a.m.
The answer is still applicative. :) On Monday Jul 26, 2010, at 10:06 AM, Kevin Jardine wrote:
On Jul 26, 3:49 pm, Kevin Jardine
wrote: I find myself wishing that f (m [a]) just automatically returned m f([a]) without me needing to do anything but I expect that there are reasons why that is not a good idea.
Or is there a monadic list module where f(m [a]) = m f ([a]) ?
It occurs to me that Haskell provides the tools to construct such a module (I think) so probably one exists?
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